If the integral $\int \frac{\cos 8x + 1}{\cot 2x - \tan 2x} dx = A \cos 8x + k,$ where $k$ is an arbitrary constant,then $A$ is equal to

  • A
    $-\frac{1}{16}$
  • B
    $\frac{1}{16}$
  • C
    $\frac{1}{8}$
  • D
    $-\frac{1}{8}$

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